2026 NRL Draw

Who do you think will get the spoon over us? Is there a worse coach than benji? Our recruitment not good. Lot of overhype
Well we didn’t get it this season and I expect us to improve as a team next season, so take your pick. I don’t know who will get it, there’s a few candidates but I don’t think it will be us.
 
Mate you're like the black sheep of the Tiger's forum, you go fairly quiet for a while and then you start wailing like a banshee again.

Stop whinging and start supporting, if the Tigers don't pass your expectations why not go for one of the top 4 teams like I'm sure there's a lot of fickle minds out in NRL land that do.
I'm a realist. I was actually quite optimistic last season with the recruitment and preseason camp etc. but it seems very little changed. I am not accepting mediocrity
 
Yeah letting AI do the draw is pathetic and clearly doesn't work, we should not have the 1st round bye again
AI needs to be trained or prompted with the expected output, and it should have governance. AI is not an excuse; whoever was in charge of the prompt engineering or the verification of output has not done their job.

Absolute rort. We'd better have the softest remaining draw in NRL history to make up for it.
 
AI needs to be trained or prompted with the expected output, and it should have governance. AI is not an excuse; whoever was in charge of the prompt engineering or the verification of output has not done their job.

Absolute rort. We'd better have the softest remaining draw in NRL history to make up for it.

No chance us getting a soft draw from the NRL unfortunately,they are probably still annoyed we missed the wooden spoon.
 
Fellow Forum Members I have dusted off the abacus and have 'attempted' to calculate the probability that one team can be given a first round bye twice in a 3 year period in a 17 team competition based on random selection. Here is the result:

The probability that a given team is awarded a first round bye in two of three consecutive years is (48⁄4913), or about 0.980 %.




In any one year only one of the 17 teams receives the first round bye, so the chance that a particular team gets it is (1⁄17).

P=1/17

Across three independent years, the number of first round byes a given team gets follows a binomial distribution;

X Bin(3, \(1⁄17)\).

We want P(X=2)


P(X=2)=(3/2)(1/17)2(1−1/17)

Compute the value.

P(X=2)=3⋅1/289⋅16/17=48/4913≈0.0098

Therefore according to this probability calculation the chances of a team being awarded a first round bye twice out of three consecutive years in a 17 team competition on a random basis is 0.0098, or less than 1%.
As always I accept NO responsibility should this arithmetic be proven wrong.
 
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